In photoelectric emission process from a metal of work function $1.8 \mathrm{eV}$, the kinetic energy of…
In photoelectric emission process from a metal of work function $1.8 \mathrm{eV}$, the kinetic energy of most energetic electrons is $0.5 \mathrm{eV}$. The corresponding stopping potential is
$1.3 \mathrm{~V}$
$0.5 \mathrm{~V}$
$2.3 \mathrm{~V}$
$1.8 \mathrm{~V}$
Solution
Stopping potential $=$ Maximum KE
$\mathrm{eV}=\mathrm{KE}_{\max }$
So, option (b) is correct.