In photoelectric effect, the stopping potential $\left(\mathrm{V}_0 ight) \mathrm{v} / \mathrm{s}$ frequency $(
u)$ curve is plotted. ( h is the Planck's constant and $\phi_0$ is work function of metal) (A) $\mathrm{V}_0 \mathrm{v} / \mathrm{s}
u$ is linear. (B) The slope of $\mathrm{V}_0…

Question

In photoelectric effect, the stopping potential $\left(\mathrm{V}_0ight) \mathrm{v} / \mathrm{s}$ frequency $(
u)$ curve is plotted. ( h is the Planck's constant and $\phi_0$ is work function of metal) (A) $\mathrm{V}_0 \mathrm{v} / \mathrm{s} 
u$ is linear. (B) The slope of $\mathrm{V}_0 \mathrm{v} / \mathrm{s} 
u$ curve $=\frac{\phi_0}{\mathrm{~h}}$ (C) h constant is related to the slope of $\mathrm{V}_0 \mathrm{v} / \mathrm{s} 
u$ line. (D) The value of electric charge of electron is not required to determine $h$ using the $V_0 \mathrm{v} / \mathrm{s} 
u$ curve. (E) The work function can be estimated without knowing the value of $h$. Choose the correct answer from the options given below :

Aicharya · Accepted Answer

$\begin{aligned}
& \mathrm{hv}=\phi+\mathrm{KE}_{\max } \\ & \mathrm{KE}_{\max }=\mathrm{eV}_0 \\ & \mathrm{~V}_0=\frac{\mathrm{hv}-\phi}{\mathrm{e}}
\end{aligned}$
(A) $\mathrm{V}_0 \mathrm{v} / \mathrm{s} \mathrm{V}$ is linear correct
(B) Slope
$\mathrm{v}_0=\left(\frac{\mathrm{h}}{\mathrm{e}}\right) \mathrm{v}-\frac{\phi}{\mathrm{e}} \text { Wrong }$
Slope $\frac{h}{e}$
(C) Correct
(D) Incorrect
(E) Correct

In photoelectric effect, the stopping potential $\left(\mathrm{V}_0\right) \mathrm{v} / \mathrm{s}$…

Solution