In parallelogram $ABCD$ with $\angle A : \angle B = 2:3$, $\angle A$ equals
In parallelogram $ABCD$ with $\angle A : \angle B = 2:3$, $\angle A$ equals
- $72^{\circ}$
- $108^{\circ}$
- $60^{\circ}$
- $90^{\circ}$
Solution
$2k + 3k = 180 \Rightarrow k = 36$. $\angle A = 72^{\circ}$.
Asked in: MH-SSC-9
Practice more Quadrilaterals questions on Aicharya