In parallelogram $ABCD$, the diagonals $AC$ and $BD$ intersect at $O$. If $AC = 16$ cm, then $AO$ is:

In parallelogram $ABCD$, the diagonals $AC$ and $BD$ intersect at $O$. If $AC = 16$ cm, then $AO$ is:
  1. $4$ cm
  2. $8$ cm
  3. $12$ cm
  4. $16$ cm

Solution

Diagonals of a parallelogram bisect each other, so $AO = \dfrac{1}{2}AC = 8$ cm.

Asked in: IMO

Practice more UNDERSTANDING QUADRILATERALS questions on Aicharya