In parallelogram $ABCD$, $\angle A = 75^{\circ}$. Then $\angle C$ is:

In parallelogram $ABCD$, $\angle A = 75^{\circ}$. Then $\angle C$ is:
  1. $75^{\circ}$
  2. $105^{\circ}$
  3. $95^{\circ}$
  4. $285^{\circ}$

Solution

$\angle A$ and $\angle C$ are opposite angles of the parallelogram, hence equal. So $\angle C = 75^{\circ}$.

Asked in: IMO

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