In parallelogram $ABCD$, $\angle A = 70^{\circ}$. Then $\angle B$ is

In parallelogram $ABCD$, $\angle A = 70^{\circ}$. Then $\angle B$ is
  1. $110^{\circ}$
  2. $70^{\circ}$
  3. $90^{\circ}$
  4. $180^{\circ}$

Solution

Adjacent angles supplementary: $180 - 70 = 110^{\circ}$.

Asked in: MH-SSC-9

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