In non-rigid diatomic molecule with an additional vibrational mode

In non-rigid diatomic molecule with an additional vibrational mode
  1. 81Cv2=49CP2
  2. 49Cv2=25CP2
  3. 49Cv2=81CP2
  4. 25Cv2=49Cp2

Solution

In non-rigid diatomic molecule with an additional vibrational mode, total degree of freedom f=3rotational+3translational+1vibrational=7

Therefore, 

CpCv=1+2f=9781Cv2=49CP2

Asked in: AP EAMCET 2022 (04 Jul Shift 2)

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