In $\mathrm{BrF}_3$ molecule, the lone pairs occupy equatorial positions to minimize:

In $\mathrm{BrF}_3$ molecule, the lone pairs occupy equatorial positions to minimize:
  1. lone pair-bond pair repulsion only
  2. bond pair-bond pair repulsion only
  3. lone pair-lone pair repulsion and lone pair-bond pair repulsion
  4. lone pair Ione pair repulsion only

Solution

In $\mathrm{BrF}_3$ molecule, the lone pair occupies equatorial position to minimize lone pair-lone pair repulsion and lone pair-bond pair repulsion as per VSEPR theory. Related Theory $\mathrm{BrF}_3$ molecular geometry is said to be T-shaped or Trigonal bipyramidal

Asked in: NEET 2004

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