In $\mathrm{PCl}_{5}$ molecule, the angle Cl-P-Cl present in a plane is equal to

In $\mathrm{PCl}_{5}$ molecule, the angle Cl-P-Cl present in a plane is equal to
  1. $180^{\circ}$
  2. $120^{\circ}$
  3. $90^{\circ}$
  4. $104^{\circ}$

Asked in: MHT CET 2020 (15 Oct Shift 2)

Practice more Chemical Bonding and Molecular Structure questions on Aicharya