In lanthanide series, the element well known to exhibit +4 oxidation state is
In lanthanide series, the element well known to exhibit +4 oxidation state is
- Lu
- $\mathrm{Ce}$
- $\mathrm{Pm}$
- $\mathrm{Nd}$
Solution
$
\begin{aligned}
\mathrm{Ce}(58) & =[\mathrm{Xe}] 4 f^1 5 d^1 6 s^2 \\
\mathrm{Ce}^{+4} & =[\mathrm{Xe}] 4 f^0 5 d^0 6 s^0
\end{aligned}
$
Cerium exihibit +4 oxidation state
Asked in: AP EAMCET 2018 (22 Apr Shift 1)
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