In isosceles $\triangle ABC$ with $AB = AC$, the angle opposite $AB$ is
In isosceles $\triangle ABC$ with $AB = AC$, the angle opposite $AB$ is
- $\angle C$
- $\angle A$
- $\angle B$
- $\angle BAC$
Solution
Angle opposite $AB$ is at vertex $C$.
Asked in: MH-SSC-9
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