In isosceles $\triangle ABC$ with $AB = AC$, the angle opposite $AB$ is

In isosceles $\triangle ABC$ with $AB = AC$, the angle opposite $AB$ is
  1. $\angle C$
  2. $\angle A$
  3. $\angle B$
  4. $\angle BAC$

Solution

Angle opposite $AB$ is at vertex $C$.

Asked in: MH-SSC-9

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