In isosceles $ riangle ABC$ with $AB = AC$ and $\angle A = 80^{\circ}$, $\angle B$ equals

Question

In isosceles $	riangle ABC$ with $AB = AC$ and $\angle A = 80^{\circ}$, $\angle B$ equals

Aicharya · Accepted Answer

$\angle B = \angle C$. $80 + 2x = 180 \Rightarrow x = 50^{\circ}$.

In isosceles $\triangle ABC$ with $AB = AC$ and $\angle A = 80^{\circ}$, $\angle B$ equals