In $\triangle \mathrm{ABC}$, if $b=2, c=\sqrt{3},\left\lfloor\mathrm{~A}=30^{\circ}\right.$, then its…

In $\triangle \mathrm{ABC}$, if $b=2, c=\sqrt{3},\left\lfloor\mathrm{~A}=30^{\circ}\right.$, then its inradius $r=$
  1. $\sqrt{3}-1$
  2. $\sqrt{3}+1$
  3. $\frac{\sqrt{3}+1}{2}$
  4. $\frac{\sqrt{3}-1}{2}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 2)

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