In hydrogen atom an electron revolves around a proton (in nucleus) at a distance ' $r$ ' $m$. the intensity…

In hydrogen atom an electron revolves around a proton (in nucleus) at a distance ' $r$ ' $m$. the intensity of electric field due to the proton at distance ' $r$ ' is $5 \times 10^{11} \mathrm{NC}^{-1}$, the magnitude of force between the electron and proton is [charge on electron $=1.6 \times 10^{-19} \mathrm{C}$ ]
  1. $4 \times 10^8 \mathrm{~N}$
  2. $8 \times 10^8 \mathrm{~N}$
  3. $4 \times 10^{-8} \mathrm{~N}$
  4. $8 \times 10^{-8} \mathrm{~N}$

Solution

$\begin{aligned} & F=q E=1.6 \times 10^{-19} \times 5 \times 10^{11} \\ & =8 \times 10^{-8} \mathrm{~N}\end{aligned}$

Asked in: MHT CET 2021 (23 Sep Shift 2)

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