In how many ways can 9 examination papers be arranged so that the best and the worst papers are never…

The number of ways in which $9$ papers can be arranged are $9!$ ways.

Take Best and Worst papers as one unit then, $\left(9-1\right)!=8!$

The best and worst papers can arrange themselves in $2!$ ways.

Total number of ways $=9!-2!\times 8!$