In how many ways a committee of a 6 members can be formed out of 10 members but always consisting of a…
In how many ways a committee of a 6 members can be formed out of 10 members but always consisting of a specified member ?
\(\frac{1}{2}{ }^9 P_5\)
\({ }^9 P_5\)
\({ }^9 \mathrm{C}_5\)
\(\frac{1}{2}{ }^9 C_5\)
Solution
As the committee consists a specified member out of 6 members, then we need to select only 5 members out of 9 remaining members and it can be done is \({ }^9 C_5\) ways. Hence, option (c) is correct.