In Hofmann bromamide degradation, one of the important steps is the migration of

1. an alkyl group without its electron pair to electron deficient $\mathrm{N}$ atom.
2. an alkyl group with its electron pair to electron deficient $\mathrm{O}$ atom.
3. an alkyl group with its electron pair to electron rich $\mathrm{N}$ atom.
4. an alkyl group with its electron pair to electron deficient $\mathrm{N}$ atom

Solution

For this one should remember that Hofmann's degradation involves migration to electron deficient nitrogen atom, hence the alkyl group will migrate with its bonding pair of electrons.
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Asked in: JEE-TOPICTESTS-CHEMISTRY

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