In Hardy-Weinberg equation, the frequency of heterozygous individual is represented by:

In Hardy-Weinberg equation, the frequency of heterozygous individual is represented by:
  1. p2
  2. 2pq
  3. pq
  4. q2

Solution

Hardy-Weinberg principle says that the sum total of all the allelic frequencies of a gene is 1 and the possible frequencies of above mentioned genotypes, i.e., AA, aa and Aa are p2, q2 and 2pq, respectively. So mathematically this statement can be written as 
p2 + 2pq + q2 = 1, where
p2 = Homozygous dominant individuals
2pq = Heterozygous individuals
q2 = Homozygous recessive individuals

Asked in: NEET 2016 (Phase 2)

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