In graphite and diamond, the percentage of $p$ characters of the hybrid orbitals in hybridization are…

In graphite and diamond, the percentage of $p$ characters of the hybrid orbitals in hybridization are respectively:
  1. $33$ and $25$
  2. $67$ and $75$
  3. $50$ and $75$
  4. $33$ and $75$

Solution

$\%$ of $p$ - in graphite $\left(s p^2\right)=\frac{2}{3} \times 100=67 \%$ $\%$ of $p$ - in diamond $\left(s p^3\right)=\frac{3}{4} \times 100=75 \%$

Asked in: JEE Main 2018 (15 Apr Shift 1 Online)

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