In gas phase $\mathrm{H}-O-O-\mathrm{H}$ bond angle in $\mathrm{H}_{2} \mathrm{O}_{2}$ is

In gas phase $\mathrm{H}-O-O-\mathrm{H}$ bond angle in $\mathrm{H}_{2} \mathrm{O}_{2}$ is
  1. $111.5^{\circ}$
  2. $94.8^{\circ}$
  3. $98.4^{\circ}$
  4. $147.5^{\circ}$

Solution

In gas phase $\mathrm{H}-\mathrm{O}-\mathrm{O}-\mathrm{H}$ bond angle in $\mathrm{H}_{2} \mathrm{O}_{2}$ is $\underline{94.8^{\circ}}$. There are lone pairs on the surface of the gas phase. oxygen and to reduce the number of lone-pair-lone pairs. The binding angle was lowered from $101.9^{\circ}$ to $101.9^{\circ}$ due to repulsion. $94.8^{\circ}$ (crystalline phase) (gas phase).

Asked in: MHT CET 2020 (16 Oct Shift 2)

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