In Dumas' method for estimation of nitrogen 1 g of an organic compound gave 150 mL of nitrogen collected at…
(Aqueous tension at $300 \mathrm{~K}=15 \mathrm{~mm} \mathrm{Hg}$)
Solution
Mole of $\mathrm{N}_2=\frac{\left(\frac{885}{760} \times 0.15\right)}{(0.0821 \times 300)}=0.0071$
Moles $\%$ of nitrogen in organic compound
$\begin{aligned}
& =\frac{(0.0071 \times 28)}{1} \times 10 \\
& =19.85 \%
\end{aligned}$
Asked in: JEE Main 2025 (04 Apr Shift 1)
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