In $\triangle PQR$ with $X$ midpoint of $PQ$, $Y$ midpoint of $PR$, and $QR = 12$. Then $XY$ is

In $\triangle PQR$ with $X$ midpoint of $PQ$, $Y$ midpoint of $PR$, and $QR = 12$. Then $XY$ is
  1. $6$
  2. $12$
  3. $3$
  4. $24$

Solution

$XY = \dfrac{1}{2} QR = 6$.

Asked in: MH-SSC-9

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