In $\triangle PQR$ with $X$ midpoint of $PQ$, $Y$ midpoint of $PR$, and $QR = 12$. Then $XY$ is
In $\triangle PQR$ with $X$ midpoint of $PQ$, $Y$ midpoint of $PR$, and $QR = 12$. Then $XY$ is
- $6$
- $12$
- $3$
- $24$
Solution
$XY = \dfrac{1}{2} QR = 6$.
Asked in: MH-SSC-9
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