In $\triangle ABC$ with $D, E$ midpoints of $AB, AC$, $DE$ is parallel to
In $\triangle ABC$ with $D, E$ midpoints of $AB, AC$, $DE$ is parallel to
- $BC$
- $AB$
- $AC$
- none
Solution
Mid-point theorem: $DE \parallel BC$.
Asked in: MH-SSC-9
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