In $\triangle ABC$ with $\angle A = 70^{\circ}, \angle B = 50^{\circ}, \angle C = 60^{\circ}$, longest side is
In $\triangle ABC$ with $\angle A = 70^{\circ}, \angle B = 50^{\circ}, \angle C = 60^{\circ}$, longest side is
- $BC$
- $AB$
- $AC$
- All equal
Solution
Largest angle $\angle A = 70^{\circ}$, opposite side $BC$ is longest.
Asked in: MH-SSC-9
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