In $\triangle ABC$, $D$ and $E$ are midpoints of $AB$ and $AC$. If $BC = 10$, then $DE$ is
In $\triangle ABC$, $D$ and $E$ are midpoints of $AB$ and $AC$. If $BC = 10$, then $DE$ is
- $5$
- $10$
- $2.5$
- $20$
Solution
$DE = \dfrac{1}{2} BC = 5$.
Asked in: MH-SSC-9
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