In $\triangle ABC$, $\angle A = 80^{\circ}$ and $\angle B = 60^{\circ}$. Largest side is
In $\triangle ABC$, $\angle A = 80^{\circ}$ and $\angle B = 60^{\circ}$. Largest side is
- $BC$
- $AB$
- $AC$
- All equal
Solution
$\angle A$ is largest, so opposite side $BC$ is longest.
Asked in: MH-SSC-9
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