In $\triangle ABC$, $AB = 8$, $BC = 6$, $AC = 5$. Smallest angle is

In $\triangle ABC$, $AB = 8$, $BC = 6$, $AC = 5$. Smallest angle is
  1. $\angle B$
  2. $\angle A$
  3. $\angle C$
  4. All equal

Solution

Smallest side $AC = 5$, opposite $\angle B$.

Asked in: MH-SSC-9

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