In $\triangle ABC$, $AB = 8, BC = 6$. Then $|AB - BC| < AC < AB + BC$ gives

In $\triangle ABC$, $AB = 8, BC = 6$. Then $|AB - BC| < AC < AB + BC$ gives
  1. $2 < AC < 14$
  2. $AC > 14$
  3. $AC = 8$
  4. $AC = 6$

Solution

$|8-6| = 2$, $8+6 = 14$. So $2 < AC < 14$.

Asked in: MH-SSC-9

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