In $\triangle ABC$, $AB = 8, BC = 6$. Then $|AB - BC| < AC < AB + BC$ gives
In $\triangle ABC$, $AB = 8, BC = 6$. Then $|AB - BC| < AC < AB + BC$ gives
- $2 < AC < 14$
- $AC > 14$
- $AC = 8$
- $AC = 6$
Solution
$|8-6| = 2$, $8+6 = 14$. So $2 < AC < 14$.
Asked in: MH-SSC-9
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