In $\mathrm{PO}_{4}^{3-}$, the formal charge on each oxygen atom and the $\mathrm{P}$ - $\mathrm{O}$ bond…

In $\mathrm{PO}_{4}^{3-}$, the formal charge on each oxygen atom and the $\mathrm{P}$ - $\mathrm{O}$ bond order respectively are
  1. $-0.75,0.6$
  2. $-0.75,1.0$
  3. $-0.75,1.25$
  4. $-3,1.25$

Solution



Bond order
$=\frac{\text { Number of bonds }}{\text { Number of Resonating structures }}$
$=\frac{5}{4}=1.25$
Three unit negative charge is being shared by four $\mathrm{O}$ atoms. Formal charge $=-3 / 4$ $=-0.75$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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