In $\left[\mathrm{Co}\left(\mathrm{NH}_{3}ight)_{6}ight] \mathrm{Cl}_{3}$, the number of covalent bonds is
In $\left[\mathrm{Co}\left(\mathrm{NH}_{3}ight)_{6}ight] \mathrm{Cl}_{3}$, the number of covalent bonds is
3
6
9
18
Solution
The number of ammonia molecules is 6 . Each ammonia molecule contains 3 covalent bonds between $\mathrm{N}$ and $\mathrm{H}$. Therefore the number of covalent bonds is 18 .
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