In compounds of type $\mathrm{ECl}_{3}$, where $\mathrm{E}=\mathrm{B}, \mathrm{P}$, As or $\mathrm{Bi}$, the…

In compounds of type $\mathrm{ECl}_{3}$, where $\mathrm{E}=\mathrm{B}, \mathrm{P}$, As or $\mathrm{Bi}$, the angles $\mathrm{Cl}-\mathrm{E}-\mathrm{Cl}$ for different $\mathrm{E}$ are in the order.
  1. $\mathrm{B}>\mathrm{P}=\mathrm{As}=\mathrm{Bi}$
  2. $\mathrm{B}>\mathrm{P}>\mathrm{As}>\mathrm{Bi}$
  3. $\mathrm{B} < \mathrm{P}=\mathrm{As}=\mathrm{Bi}$
  4. $\mathrm{B} < \mathrm{P} < \mathrm{As} < \mathrm{Bi}$

Solution



(Trigonal planar geometry); Bond angle $=120^{\circ}$

In these, order of bond angle:
$\mathrm{BCl}_{3}>\mathrm{PCl}_{3}>\mathrm{AsCl}_{3}>\mathrm{BiCl}_{3}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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