In common emitter configuration of a transistor, current gain is more than 1 because…

In common emitter configuration of a transistor, current gain is more than 1 because $\left[\mathrm{I}_{\mathrm{b}}, \mathrm{I}_{\mathrm{e}}\right.$ and $\mathrm{I}_{\mathrm{c}}$ are base, emitter and collector currents respectively
  1. $\mathrm{I}_{\mathrm{c}} < \mathrm{I}_{\mathrm{b}}$
  2. $\mathrm{I}_{\mathrm{b}} < \mathrm{I}_{\mathrm{e}}$
  3. $\mathrm{I}_{\mathrm{c}} < \mathrm{I}_{\mathrm{e}}$
  4. $\mathrm{I}_{\mathrm{c}}>\mathrm{I}_{\mathrm{b}}$

Solution

In the common-emitter configuration of a transistor, the current gain is more than 1 because $\left[l_b, l_e\right.$, and $1_c$ are base, emitter, and collector currents respectively] $\mathbf{I}_{\mathbf{c}}>\mathbf{I}_{\mathbf{b}}$.

Asked in: MHT CET 2020 (20 Oct Shift 1)

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