In common emitter amplifier, input resistance is $1000 \Omega$, peak value of input signal voltage is $5…

In common emitter amplifier, input resistance is $1000 \Omega$, peak value of input signal voltage is $5 \mathrm{mV}$ and $\beta=60$. The peak value of output current is
  1. $0.5 \times 10^{-4} \mathrm{~A}$
  2. $3 \times 10^{-4} \mathrm{~A}$
  3. $2 \times 10^{-5} \mathrm{~A}$
  4. $1 \times 10^{-5} \mathrm{~A}$

Solution

$r_{L}=1000 \Omega$ $v_{i}=5 \mathrm{mV}=5 \times 10^{-3} \mathrm{~V}$ $\beta=60$ $I_{\text {input }}=\frac{5 \times 10^{-3}}{1000}=5 \times 10^{-6} \mathrm{~A}$ $\therefore I_{\text {output }}=60 \times 5 \times 10^{-6} \mathrm{~A}=300 \times 10^{-6} \mathrm{~A}$ $=3 \times 10^{-4} \mathrm{~A}$

Asked in: MHT CET 2020 (16 Oct Shift 1)

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