In circle of radius $5$ cm, two equal chords are each at distance $3$ cm from centre. Length of each is
In circle of radius $5$ cm, two equal chords are each at distance $3$ cm from centre. Length of each is
- $8$ cm
- $4$ cm
- $10$ cm
- $6$ cm
Solution
Half-chord $= \sqrt{25-9} = 4$. Chord $= 8$.
Asked in: MH-SSC-9
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