In case of photoelectric effect, the graph of measured stopping potential $\left(\mathrm{V}_0\right)$…

In case of photoelectric effect, the graph of measured stopping potential $\left(\mathrm{V}_0\right)$ against frequency ' $v$ ' of incident light is a straight line. The slope of this line multiplied by the charge of electron (e) gives
  1. the work function of the metal.
  2. the Planck's constant.
  3. the maximum kinetic energy of the ejected electrons.
  4. the threshold frequency for photoejection from the metal.

Solution

We know that, $\begin{aligned} & \mathrm{V}_0=\frac{\mathrm{h} \nu}{\mathrm{l}}-\frac{\mathrm{h} \mathrm{v}_0}{l} \\ & \mathrm{y}=\mathrm{mx}+\mathrm{c} \end{aligned}$
The slope of this line is $\frac{\mathrm{h}}{l}$ According to the question, $\frac{\mathrm{h}}{l} \times \mathrm{e}$ $\therefore \quad$ The slope of line is ' $h$ ' (Planck's constant).

Asked in: MHT CET 2024 (11 May Shift 2)

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