In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl. The percentage composition of chlorine in the compound is _______ %.
(Given : molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ of $\mathrm{Ag}: 108, \mathrm{Cl}: 35.5$)

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{n}_{\mathrm{Cl}}=\mathrm{n}_{\mathrm{AgCl}}=\frac{143.5 	imes 10^{-3}}{143.5}=10^{-3} \ & \% \mathrm{Cl}=\frac{10^{-3} 	imes 35.5}{180 	imes 10^{-3}} 	imes 100=19.72\end{aligned}$

In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl. The…

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