In $\mathrm{n}^{\text {th }}$ Bohr orbit, the ratio of the kinetic energy of an electron to the total energy…

In $\mathrm{n}^{\text {th }}$ Bohr orbit, the ratio of the kinetic energy of an electron to the total energy of it, is
  1. 2:1
  2. 1:-1
  3. 1:1
  4. -1:2

Solution

Kinetic energy $=-$ Total energy

Asked in: MHT CET 2021 (22 Sep Shift 2)

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