In biprism experiment, the fringe width is 0.6 mm . The distance between $6^{\mathrm{th}}$ dark fringe and $8^{ ext {th }}$ bright fringe on the same side of central bright fringe is

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In biprism experiment, the fringe width is 0.6 mm . The distance between $6^{\mathrm{th}}$ dark fringe and $8^{	ext {th }}$ bright fringe on the same side of central bright fringe is

Aicharya · Accepted Answer

For $8^{	ext {th }}$ bright fringe, $\mathrm{x}_8=8 \mathrm{X}$ For $6^{	ext {th }}$ dark fringe, $\begin{aligned} & x_6=\left(6-\frac{1}{2}ight) X=5.5 X \ & x_8-x_6=8 X-5.5 X=2.5 X \ 	herefore \quad & x_8-x_6=2.5 	imes 0.6=1.5 \mathrm{~mm} \end{aligned}$

In biprism experiment, the fringe width is 0.6 mm . The distance between $6^{\mathrm{th}}$ dark fringe and…

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