In any Bohr orbit of hydrogen atom, the ratio of K.E to P.E of revolving electron at a distance '…
In any Bohr orbit of hydrogen atom, the ratio of K.E to P.E of revolving electron at a distance ' $\mathrm{r}^{\prime}$ from the nucleus is
- $-1$
- $+\frac{1}{2}$
- 1
- $-\frac{1}{2}$
Solution
kinetic energy $\quad \mathrm{k}=\frac{1}{8 \pi \epsilon_{0}} \cdot \frac{\mathrm{e}^{2}}{\mathrm{r}}$
Potential energy $P=-\frac{1}{4 \pi \epsilon_{\mathrm{o}}} \cdot \frac{\mathrm{e}^{2}}{\mathrm{r}}$
$\therefore \frac{\mathbf{k}}{\mathrm{p}}=-\frac{1}{2}$
Asked in: MHT CET 2020 (14 Oct Shift 1)
Practice more Structure of Atoms and Nuclei questions on Aicharya