In an L C R series circuit, an inductor 30   mH and a resistor 1   Ω are connected to an AC source of angular frequency 300   rad   s - 1 . The value of capacitance for which the current leads the voltage by 45 ° is 1 x × 10 - 3   F . Then the value of x is

Question

In an L C R series circuit, an inductor 30 &#160; mH and a resistor 1 &#160; &#937; are connected to an AC source of angular frequency 300 &#160; rad &#160; s - 1 . The value of capacitance for which the current leads the voltage by 45 &#176; is 1 x &#215; 10 - 3 &#160; F . Then the value of x is

Aicharya · Accepted Answer

tan &#981; = x C - x L R tan 45 = x C - x L R x C - x L = R 1 &#969; C - &#969; L = R 1 &#969; C - 300 &#215; 0 . 03 = 1 1 &#969; C = 10 C = 1 10 &#969; = 1 10 &#215; 300 C = 1 3 &#215; 10 - 3 X = 3

In an L C R series circuit, an inductor 30   mH and a resistor 1   Ω are connected to an AC…

Solution

In an L C R series circuit, an inductor 30 &#160; mH and a resistor 1 &#160; &#937; are connected to an AC…

Solution

In an L C R series circuit, an inductor 30 mH and a resistor 1 Ω are connected to an AC…