In an examination hall there are ' \(m n\) ' chairs in \(m\) rows and \(n\) columns. The number of ways in…
- \(m^n n\) !
- \(n^m m\) !
- \(m^m n !\)
- \(n^n m\) !
Solution

\(\therefore\) Number of ways in which one student can seat in Ist column \(=n\) So, similarly \(m\) students can seat in \(n^m\) ways. Since, students can be arranged in \(m\) ! ways, \(\therefore\) Total number of ways \(=m ! \times n^m\) ways
Asked in: AP EAMCET 2019 (22 Apr Shift 1)