In an ellipse, two vertices are \((5,0)\) and \((0,-4)\). Then the equation of the ellipse is

In an ellipse, two vertices are \((5,0)\) and \((0,-4)\). Then the equation of the ellipse is
  1. \(\frac{x^2}{16}+\frac{y^2}{25}=1\)
  2. \(\frac{x^2}{25}+\frac{y^2}{16}=1\)
  3. \(\frac{x^2}{5}+\frac{y^2}{4}=1\)
  4. \(x^2+y^2=41\)

Solution

Equation of ellipse having vertices \((5,0)\) and \((0,-4) \text { is } \frac{x^2}{25}+\frac{y^2}{16}=1\)

Asked in: AP EAMCET 2020 (18 Sep Shift 1)

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