In an ellipse, the distance between its foci is 6 and minor axis is 8. Then its eccentricity is

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Aicharya · Accepted Answer

$2 a e=6 \Rightarrow a e=3$ $2 b=8 \Rightarrow b=4$ $b^2=a^2\left(1-e^2ight)$ $16=a^2-a^2 e^2$ $a^2=16+9=25$ $a=5$ $	herefore e=\frac{3}{a}=\frac{3}{5}$

In an ellipse, the distance between its foci is 6 and minor axis is 8. Then its eccentricity is

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