In an atom, electron of charge (-e) performs U.C.M. around a stationary positively charged nucleus, with…

In an atom, electron of charge (-e) performs U.C.M. around a stationary positively charged nucleus, with period of revolution 'T'. If 'r' is the radius of the orbit of the electron and ' $\mathrm{v}^{\prime}$ is the orbital velocity, then the circulating current (I) is proportional to
  1. $\mathrm{e}^{1} \mathrm{r}^{-1} \mathrm{v}^{-1}$
  2. $\mathrm{e}^{1} \mathrm{r}^{1} \mathrm{~V}^{-1}$
  3. $\mathrm{e}^{1} \mathrm{~V}^{1} \mathrm{r}^{-1}$
  4. $\mathrm{v}^{1} \mathrm{r}^{1} \mathrm{e}^{-1}$

Solution

In an atom, electron of charge $(-e)$ perform U.C.M. around a stationary positively charged nucleus, with period of revolution $\mathrm{'T'}$. If $' r^{\prime}$ is the radius of the orbit of the electron and ' $v$ ' is the orbital velocity, then the circulating current $\mathrm{(I)}$ is proportional to $\underline{\mathbf{e}}^{\mathbf{1}}$ $\underline{\mathbf{v}}^{\mathbf{1}}$ $\underline{\mathbf{r}}^{\mathbf{-1}}$. $\frac{2 \pi r}{\mathrm{T}}=v$ $\mathrm{I}=\frac{\mathrm{e}}{\mathrm{T}}=\frac{\mathrm{ev}}{2 \pi \mathrm{r}}=\mathrm{e}^{1} \mathrm{v}^{1} \mathrm{r}^{-1} \frac{1}{2} \pi$ $\mathrm{I} \propto e^{1} v^{1} r^{-1}$

Asked in: MHT CET 2020 (20 Oct Shift 2)

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