In an ammeter, 5 % of the main current passes through the galvanometer. If resistance of the galvanometer is…

In an ammeter, 5% of the main current passes through the galvanometer. If resistance of the galvanometer is G, the resistance of ammeter will be:
  1. G20
  2. G199
  3. 199 G
  4. 200 G

Solution

As potential drop across both branches would be the same, we get ISS=IgG

95100IS=5I100G

⇒S=G19

Now, resistance of ammeter will be

RA=SGS+G=G21920G19

⇒RA=G20

Asked in: JEE Main 2024 (01 Feb Shift 2)

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