In an alkaline condition $\mathrm{KMnO}_{4}$ reacts as follows:
$2 \mathrm{KMnO}_{4}+2 \mathrm{KOH} ightarrow 2 \mathrm{~K}_{2} \mathrm{MnO}_{4}+\mathrm{H}_{2} \mathrm{O}+\mathrm{O}$
Its equivalent weight is

Question

Aicharya · Accepted Answer

Change in O.S. is by $1 .$ Hence eq. wt. is $\frac{158}{1}=158$

In an alkaline condition $\mathrm{KMnO}_{4}$ reacts as follows: $2 \mathrm{KMnO}_{4}+2 \mathrm{KOH}…

Solution