In an adsorption experiment, a graph between log ( x / m ) versus logP was found to be linear with a slope of 45 ° . The intercept on log ( x / m ) axis was found to be 0 . 3010 . The amount of gas adsorbed per gram of charcoal under a pressure of 0 . 5   atm is

Question

In an adsorption experiment, a graph between log ( x / m ) versus logP was found to be linear with a slope of 45 &#176; . The intercept on log ( x / m ) axis was found to be 0 . 3010 . The amount of gas adsorbed per gram of charcoal under a pressure of 0 . 5 &#160; atm is

Aicharya · Accepted Answer

According to the Freundlich's Adsorption Isotherm,

$\frac{x}{m} = k \cdot p^{1 / n}$

By taking the log both sides,

$\log \frac{x}{m} = logk + \frac{1}{n} logp$

So, slope $= \frac{1}{n} \Rightarrow \tan 45 ° = 1 (n = 1)$

$logK = 0.3010 \Rightarrow k = 2$

$\frac{x}{m} = 2 {(0.5)}^{\frac{1}{n}} \frac{x}{m} = 1$

Hence, the amount of gas adsorbed per gram of charcoal under a pressure of

0.5 atm

is

1.0 g

In an adsorption experiment, a graph between log ( x / m ) versus logP was found to be linear with a slope…

Solution