In an acid-base titration, 0.1   M   H C l solution was added to the N a O H solution of unknown strength. Which of the following correctly shown the change of p H of the titration mixture in this experiment?

Question

In an acid-base titration, 0.1 &#160; M &#160; H C l solution was added to the N a O H solution of unknown strength. Which of the following correctly shown the change of p H of the titration mixture in this experiment?

Aicharya · Accepted Answer

For titration of strong base with strong acid

p H

changes sharply near equivalence point and at equivalent point

p H

sharply decreases because strong base & strong acid dissociate completely.

\overset{S A}{H C l} + \overset{S B}{N a O H} \to N aCl + H_{2} O (l)

at equivalent point

p H = 7

and at endpoint solution will be neutral.

In an acid-base titration, 0.1   M   H C l solution was added to the N a O H solution of unknown…

Solution

In an acid-base titration, 0.1 &#160; M &#160; H C l solution was added to the N a O H solution of unknown…

Solution

In an acid-base titration, 0.1 M H C l solution was added to the N a O H solution of unknown…