In an a.c. circuit $I=100 \sin 200 \pi t$. The time required for the current to achieve its peak value will be

In an a.c. circuit $I=100 \sin 200 \pi t$. The time required for the current to achieve its peak value will be
  1. $\frac{1}{100} \mathrm{~s}$
  2. $\frac{1}{200} \mathrm{~s}$
  3. $\frac{1}{300} \mathrm{~s}$
  4. $\frac{1}{400} \mathrm{~s}$

Solution

$I=100 \sin 200 \pi t$ Peak value $\mathrm{I}_0=100 \mathrm{~A}$ When $\mathrm{I}=100 \mathrm{~A}$, we have $100=100 \sin 200 \pi \mathrm{t}$ $\therefore \quad \sin 200 \pi \mathrm{t}=1$ $\therefore \quad 200 \pi \mathrm{t}=\frac{\pi}{2}$ $\therefore \quad \mathrm{t}=\frac{1}{400} \mathrm{~s}$

Asked in: MHT CET 2024 (02 May Shift 1)

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