In an a.c. circuit $I=100 \sin 200 \pi t$. The time required for the current to achieve its peak value will be
In an a.c. circuit $I=100 \sin 200 \pi t$. The time required for the current to achieve its peak value will be
- $\frac{1}{100} \mathrm{~s}$
- $\frac{1}{200} \mathrm{~s}$
- $\frac{1}{300} \mathrm{~s}$
- $\frac{1}{400} \mathrm{~s}$
Solution
$I=100 \sin 200 \pi t$
Peak value $\mathrm{I}_0=100 \mathrm{~A}$
When $\mathrm{I}=100 \mathrm{~A}$, we have
$100=100 \sin 200 \pi \mathrm{t}$
$\therefore \quad \sin 200 \pi \mathrm{t}=1$
$\therefore \quad 200 \pi \mathrm{t}=\frac{\pi}{2}$
$\therefore \quad \mathrm{t}=\frac{1}{400} \mathrm{~s}$
Asked in: MHT CET 2024 (02 May Shift 1)
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