In an AC circuit $V$ and $I$ are given below, then find the power dissipated in the circuit $V=50 \sin (50 t) v I=50 \sin \left(50 t+\frac{\pi}{3}\right) \mathrm{mA}$

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Aicharya · Accepted Answer

$\mathrm{P}=\mathrm{E}_{\mathrm{rms}} \mathrm{V}_{\mathrm{rms}} \cos 	heta=\frac{E_0 V_0}{2} \cos \phi$ So, $\quad P=\frac{50 	imes 50 	imes 10^{-3} 	imes 1}{2 	imes 2}=0.625 \mathrm{~W}$

In an AC circuit $V$ and $I$ are given below, then find the power dissipated in the circuit $V=50 \sin (50…

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